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Hcf of 1288 and 575

WebAug 13, 2024 · Find the HCF of 55 and 210 . express it as a linear combinaton of 55 and 210, i.e. HCF of 55 and 210= 210a +55b, for some a andb asked Sep 17, 2024 in … Web1288 = 575 x 2+ 138. Since remainder ≠ 0, apply division lemma on divisor 506 and remainder 143 575 = 138 x 4 + 23. Since remainder ≠ 0, apply division lemma on divisor 143 and remainder 77 138 = 23 x 6 + 0. Therefore, H.C.F. = 23. Now, 23 = 575 – 138 x 4 = 575 - [1288 – 575 x 2] x 4 = 575 - 1288 x 4 + 575 x 8 = 575 x 9 - 1288 x 4 Hence, obtained.

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WebOct 10, 2024 · Find the HCF of the following pair of integers and express it as a linear combination of them 1288 and 575 - Given: 1288 and 575. To do: Here we have to find the HCF of the given pair of integers and express it as a linear combination. Solution: Using Euclid's division algorithm to find HCF: Using Euclid’s lemma to get: $1288 = 575 times 2 … Calculate GCF, GCD and HCFof a set of two or more numbers and see the work using factorization. Enter 2 or more whole numbers separated by commas or spaces. The Greatest Common Factor Calculator solution also works as a solution for finding: 1. Greatest common factor (GCF) 2. Greatest common … See more The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF= 6. See more Any non zero whole number times 0 equals 0 so it is true that every non zero whole number is a factor of 0. k × 0 = 0 so, 0 ÷ k = 0 for any whole number k. For example, 5 × 0 = 0 … See more There are several ways to find the greatest common factor of numbers. The most efficient method you use depends on how many numbers you … See more china youth travel service https://gokcencelik.com

(i) 963 and 657 (ii) 592 and 252 (iii) 506 and 1155 (iv) 1288 and 575

WebOct 11, 2024 · Find the HCF and express as linear combination of them : 1288 and 575 ... Doubtnut 2.7M subscribers Subscribe 4.7K views 4 years ago To ask Unlimited Maths doubts download … WebAug 8, 2024 · = 575 x 9 – 1288 x 4. Question 4. Find the largest number which divides 615 and 963 leaving remainder 6 in each case. Solution: Firstly, since 6 is required as the … WebOct 10, 2024 · Therefore the HCF of 1288 and 575 is the divisor at this stage, i.e., 23. Expressing the HCF as a linear combination of 963 and 657: 23 = 575 – 138 × 4 {from … grand banks nyc happy hour

Find the HCF of the following pair of integers and express it as a ...

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Hcf of 1288 and 575

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WebHCF of 1288, 575 is 23 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example. Consider we have numbers 1288, 575 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r ... WebUse Euclid's division algorithm to find the HCF of 1288,575 Easy Solution Verified by Toppr 575)1288(2 1150 ____________________ 138)575(4 552 _________________ …

Hcf of 1288 and 575

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WebQ. Find the HCF of the following pairs of integers and express it as a linear combination of them. (i) 963 and 657 (ii) 592 and 252 (iii) 506 and 1155 (iv) 1288 and 575 Q. Find HCF of 210 and 55 and express it as a linear combination of 210 and 55 Q. WebWrite each number as a product of its prime factors. 2 2 x 3 x 5 = 60. 3 x 5 2 = 75. The product of all common prime factors is the HCF. The common prime factors in this example are 3 & 5. The lowest power of 3 is 3 and 5 is 5. So, HCF = 3 x 5 = 15. Example 2: Find the HCF of 36, 24 and 12.

WebFeb 21, 2024 · Define HCF of two positive integers and find the HCF of the following pairs of numbers: (i) 75 and 243 (ii)240 and 6552 askedApr 22, 2024in Number Systemby Madhuwant(38.1kpoints) real numbers class-10 0votes 1answer Using Euclid's algorithm, find the HCF of 240 and 228. askedSep 28, 2024in Mathematicsby Minu(46.3kpoints) … WebUse Euclid's division algorithm to find the HCF of 1288 and 575. Check whether 5 × 3 × 11 + 11 and 5 × 7 + 7X 3 are composite number and justify Check whether 6n can end with …

Web1288 and 575 Solution The correct option is A 963 and 657 To express HCF (of 963 and 657) as a linear combination of them means HCF = 963x + 657y. Using Euclid Division Lemma we get HCF as 9. a =bq+r,0≤r < b 963 =657×1+306 657 =306×2+45 306 =45×6+36 45 =36×1+9 36 =9×4+0 ∴ HCF (657, 963)=9. Web1288 = 575 x 2+ 138. Since remainder ≠ 0, apply division lemma on divisor 506 and remainder 143. 575 = 138 x 4 + 23. Since remainder ≠ 0, apply division lemma on divisor …

WebMay 6, 2015 · Applying division algorithm to 1288 and 575 1288 = 575 × 2 + 138 575 = 138 × 4 + 23 138 = 23 × 6 + 0 The remainder has now become zero, so our procedure stops . Since the divisor at this stage is 23. The …

WebFind the HCF of the following pairs of integers and express it as a linear combination of 1288 and 575. VIEW SOLUTION Exercise 1.2 Q 4 Page 27 Find the largest number which divides 615 and 963 leaving remainder 6 in each case. VIEW SOLUTION Exercise 1.2 Q 5 Page 27 grand banks power \u0026 motoryacht adWebFeb 21, 2024 · For 1288 and 575 we find their factors and then find the highest common factor Factors of 1288 are $1,2,4,7,8,14,23,28,46,56,92,161,184,322,644,1288$. Factors of 575 are $1,5,23,25,115,575$. The highest common factor is 23. We can also express H.C.F as \[\begin{align} & 23\left \!{\underline {\, 1288,575 \,}} \right. & 1\left \!{\underline {\, china y rusherkingWebFind the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively. Medium. View solution. grand banks performance sweatshirtWebDec 3, 2013 · 1288 = 2 × 575 + 138. 575 = 4 ×138 + 23. 138 = 6 × 23 + 0. Hence the HCF of 1288 and 575 is 23. Recommend (0) Comment (0) person. Kishore Kumar. 1288 = 2 … china youzan investor relationsWebDetailed Answer: The Greatest Common Factor (GCF) for 58 and 87, notation CGF (58,87), is 29. Explanation: The factors of 58 are 1,2,29,58; The factors of 87 are … grand banks tachometerWebHCF of 506 and 1155 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. Step 1: Divide 1155 (larger number) by 506 (smaller number). Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (506) by the remainder (143). Step 3: Repeat this process until the remainder = 0. china youtube channelWebClick here👆to get an answer to your question ️ Use Eucid's division algorithm to find the HCF of 1288 and 575 Check whether \( 5 \times 3 x + 1 + 1 ! \) and \( 5 x 7 + 7 \times 3 \) are composite number and justify Check whether \( 6 ^ { \text {t } } \) can end with the digit 0 , where \( n \) is any natural number china young mens winter coats factory